Quantcast
Channel: Necessary and sufficient conditions for the Cayley graph to be bipartite - MathOverflow
Browsing index pages (2 articles)
↧

Necessary and sufficient conditions for the Cayley graph to be bipartite

Let $G$ be a finite group with identity $1$. If $S$ be an inverse closed generated subset of $G$, then $S$ is called a Cayley subset of $G$.The Cayley graph $\Gamma=\operatorname{Cay}(G, S)$ is a...

View Article


Answer by Corentin B for Necessary and sufficient conditions for the Cayley...

The Cayley graph is bipartite if and only if there exists a homomorphism $\pi\colon G\to\mathbb Z/2\mathbb Z=\{0,1\}$ such that $\pi(S) \subseteq \{1\}$.If such a map exists, then the sets...

View Article

Browsing index pages (2 articles)


Latest Images